mirror of
https://github.com/ClemensFischer/XAML-Map-Control.git
synced 2025-12-06 07:12:04 +01:00
154 lines
5.2 KiB
C#
154 lines
5.2 KiB
C#
// XAML Map Control - https://github.com/ClemensFischer/XAML-Map-Control
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// © 2021 Clemens Fischer
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// Licensed under the Microsoft Public License (Ms-PL)
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using System;
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using System.Globalization;
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namespace MapControl
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{
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/// <summary>
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/// A geographic location with latitude and longitude values in degrees.
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/// </summary>
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#if !WINDOWS_UWP
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[System.ComponentModel.TypeConverter(typeof(LocationConverter))]
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#endif
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public class Location : IEquatable<Location>
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{
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private double latitude;
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private double longitude;
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public Location()
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{
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}
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public Location(double latitude, double longitude)
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{
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Latitude = latitude;
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Longitude = longitude;
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}
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public double Latitude
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{
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get { return latitude; }
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set { latitude = Math.Min(Math.Max(value, -90d), 90d); }
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}
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public double Longitude
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{
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get { return longitude; }
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set { longitude = value; }
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}
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public bool Equals(Location location)
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{
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return location != null
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&& Math.Abs(location.latitude - latitude) < 1e-9
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&& Math.Abs(location.longitude - longitude) < 1e-9;
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}
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public override bool Equals(object obj)
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{
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return Equals(obj as Location);
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}
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public override int GetHashCode()
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{
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return latitude.GetHashCode() ^ longitude.GetHashCode();
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}
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public override string ToString()
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{
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return string.Format(CultureInfo.InvariantCulture, "{0:F5},{1:F5}", latitude, longitude);
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}
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public static Location Parse(string locationString)
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{
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Location location = null;
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if (!string.IsNullOrEmpty(locationString))
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{
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var values = locationString.Split(new char[] { ',' });
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if (values.Length != 2)
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{
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throw new FormatException("Location string must be a comma-separated pair of double values.");
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}
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location = new Location(
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double.Parse(values[0], NumberStyles.Float, CultureInfo.InvariantCulture),
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double.Parse(values[1], NumberStyles.Float, CultureInfo.InvariantCulture));
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}
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return location;
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}
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/// <summary>
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/// Normalizes a longitude to a value in the interval [-180 .. 180].
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/// </summary>
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public static double NormalizeLongitude(double longitude)
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{
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if (longitude < -180d)
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{
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longitude = ((longitude + 180d) % 360d) + 180d;
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}
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else if (longitude > 180d)
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{
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longitude = ((longitude - 180d) % 360d) - 180d;
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}
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return longitude;
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}
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/// <summary>
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/// Calculates the great circle distance between this and the specified Location.
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/// https://en.wikipedia.org/wiki/Great_circle
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/// https://en.wikipedia.org/wiki/Great-circle_distance
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/// https://en.wikipedia.org/wiki/Great-circle_navigation
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/// </summary>
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public double GetDistance(
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Location location, double earthRadius = MapProjection.Wgs84EquatorialRadius)
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{
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var lat1 = latitude * Math.PI / 180d;
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var lon1 = longitude * Math.PI / 180d;
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var lat2 = location.latitude * Math.PI / 180d;
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var lon2 = location.longitude * Math.PI / 180d;
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var sinLat1 = Math.Sin(lat1);
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var cosLat1 = Math.Cos(lat1);
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var sinLat2 = Math.Sin(lat2);
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var cosLat2 = Math.Cos(lat2);
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var sinLon12 = Math.Sin(lon2 - lon1);
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var cosLon12 = Math.Cos(lon2 - lon1);
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var a = cosLat1 * sinLat2 - sinLat1 * cosLat2 * cosLon12;
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var b = cosLat2 * sinLon12;
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var s12 = Math.Atan2(Math.Sqrt(a * a + b * b), sinLat1 * sinLat2 + cosLat1 * cosLat2 * cosLon12);
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return earthRadius * s12;
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}
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/// <summary>
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/// Calculates the Location on a great circle at the specified azimuth angle and distance from this Location.
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/// https://en.wikipedia.org/wiki/Great_circle
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/// https://en.wikipedia.org/wiki/Great-circle_navigation
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/// </summary>
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public Location GetLocation(
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double azimuth, double distance, double earthRadius = MapProjection.Wgs84EquatorialRadius)
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{
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var s12 = distance / earthRadius;
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var az1 = azimuth * Math.PI / 180d;
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var lat1 = latitude * Math.PI / 180d;
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var lon1 = longitude * Math.PI / 180d;
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var sinS12 = Math.Sin(s12);
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var cosS12 = Math.Cos(s12);
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var sinAz1 = Math.Sin(az1);
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var cosAz1 = Math.Cos(az1);
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var sinLat1 = Math.Sin(lat1);
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var cosLat1 = Math.Cos(lat1);
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var lat2 = Math.Asin(sinLat1 * cosS12 + cosLat1 * sinS12 * cosAz1);
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var lon2 = lon1 + Math.Atan2(sinS12 * sinAz1, (cosLat1 * cosS12 - sinLat1 * sinS12 * cosAz1));
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return new Location(lat2 * 180d / Math.PI, lon2 * 180d / Math.PI);
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}
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}
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}
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